1.Base your answer to the following question on The diagram below shows columns A, B, C, and D that contain different sediments. 1)A 2)B 3)C 4)D Equal volumes of water were poured through each column. Which column of sediment retained the most water? 1)clay 2)silt 3)sand 4)pebbles 2.Which sediment size would allow water to flow through at the ...
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Similarly, we add R 3 = (B, D), and R 4 = (E, A). 3) R1 contains a candidate key for R, therefore we do not need to add a relation consisting of a candidate key. Finally, the received decomposition is (A, B, C), (C, D, E), (B, D), (E, A). I. Suppose we have a database for an investment firm, consisting of the following attributes: B – Broker,
SOLUTION 485 lb .- PROBLEM 3.72 Four pegs of the same diameter are attached to a board as shown. Two strings are passed around the pegs and pulled with the forces indicated. Determine the diameter of the pegs knowing that the resultant couple applied to the board is 485 lb . counterclockwise. AD AD BC - + d) in.l(35 1b) + d) 1b) 1.250 in.
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(ÐA and ÐB are supplementary) AD||BC When a transversal (AB) cuts two lines (AD and BC), and the angles on the same side of the transversal (ÐA and ÐB) are suplementary, the lines are parallel. m/C + m/B = 180° Substituting m Ð C for m Ð A in equation 2 steps back.
SF B x = =0: 0 x B B= y + SM A = 0 50 100 0 45 150 0 9 0 9 0: ( ) ( )( . ) ( )( . ) ( . )N N m N md - - -d - + - =d B dm 50 45 100 135 150 0 9d d d B Bd- + - + + -. d B A B = --180 0 9 300 N m ( . m) (1) + SM B = 0 50 0 9 0 9 100: ( )( . ) ( . ) (N m m N)(0.45m)- - +A d = 0 45 0 9 45 0- + + =. A Ad d A A = (0.9 m) 90 N m- (2) Since B˜180 N, Eq ...
The ML Aggarwal Solutions for Class 10 Maths Chapter 13 given here are available for free. Students can download these PDFs and start practising offline. Chapter 13 – Similarity. Similarity is an idea in geometry. It means that two polygons, line segments, or other figures have the same shape. Similar objects do not need to have the same size.
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E b a a a a B C D F Solution Joist BF. Since b a = 30 ft 10 ft = 3, the concrete slab will behave as a one-way slab. Thus, the tributary area for this joist is the rectangular area shown in Fig. a, and the intensity of the uniform distributed load is [email protected]@thick reinforced 3stone concrete slab: (0.15 k>ft )a 4 …
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Question 1: ABC is a triangle and D is the mid-point of BC. The perpendiculars from D to AB and AC are equal. Prove that the triangle is isosceles. Solution: Given: D is the midpoint of BC and PD = DQ in a triangle ABC. To prove: ABC is isosceles triangle. In BDP and CDQ. PD = QD (Given) BD = DC (D is mid-point) ∠BPD = ∠CQD = 90 o
You can put this solution on YOUR website! ... B congruent to D Draw diagonal BD AB parallel to CD opposite sides of a parallelogram angle ABD congruent to angle CDB alternate interior angles when transversal BD cut parallel lines AB and CD AD parallel to CB opposite sides of a parallelogram angle ...
3. a) truth table b) sop y0 = (a''b''c''d)+(a''b''cd'')+(a''bc''d'')+(a''bcd)+(ab''c''d'')+(ab''cd)+(abc''d)+(a bcd'') y1= (a''b''cd)+(a''bc''d ...
· Point A, B, C and D lies on a straight line AB : BD = 1:5 AC : CD = 7:11 Work out AB : BC : CD
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(a) 17 cm (b) 15 cm (c) 4 cm (d) 8 cm Solution: (d) Given, AD = 34 cm and AB = 30 cm In figure, draw OL ⊥ AB. Since, the perpendicular from the centre of a circle to a chord bisects the chord. Question 2: In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to
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two links joining B and D, determine the allowable load P if an overall factor of safety of 3.0 is desired. 12 mm ABC 0.18 S mm 0.20 o o CD. 20 = 12 FA 0.20 10 160 3.77 N 337 S mm 12 mm Side View 10 10 3.0 5.82 N 113. 1b 3.97 N go Based compress BD one Value A = (0.020 = 250 x/o'' )( ICO ) .
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· Prove that ABC is an isosceles triangle. Solution: Question 10. In the given figure, AD, BE and CF arc altitudes of ∆ABC. If AD = BE = CF, prove that ABC is an equilateral triangle. Solution: Question 11. In a triangle ABC, AB = AC, D and E are points on the sides AB and AC respectively such that BD = CE. Show that:
A) AB >BC B) AC >BC C) AC <BA D) BC <BA 30. A rectangular prism has a base with a length of 25, a width of 9, and a height of 12. A second prism has a square base with a side of 15. If the volumes of the two prisms are equal, what is the height of the second prism? A) 6 B) 8 C) 12 D) 15 31. What is the perimeter of a rhombus whose diagonals are ...
d B i d t = Σ j = 1 n μ max, i j B i E D j K i j + E D j K i E A + E A = Σ j = 1 n μ max, i j B i F K, i j (3) where n is the number of E D ''s sustaining the growth of biomass group i, and F K, i j are dimensionless kinetic limitation terms (0-1) for each of the j catabolic reaction that are function of the uptake efficiencies of the E D ...
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of the 300-N force about D, (b) the magnitude and sense of the horizontal force applied at C that creates the same moment about D, (c) the smallest force applied at C that creates the same moment about D. 0.2 m C D 0.125 m a a SOLutiOn (a) See Problem 3.3 for the figure and analysis leading to the determination of M D M D = 41.7 N m 0.2 m
L''angle C''B''D'' est également droit. La longueur C''D'' est égale à 5×1,5=7,5cm D'' appartient donc au cercle de centre C'' et de rayon 7,5 cm. On peut donc construire le point D'' car il appartient également à a perpendiculaire à [B''C''] passant par B'' 3G1 – Théorème de Thalès – page 8